## RS Aggarwal Class 6 Solutions Chapter 10 Ratio, Proportion and Unitary Method Ex 10C

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10C.

**Other Exercises**

**Question 1.****Solution:**

Cost of 14 m of cloth = Rs. 1890

Cost of 1 m = Rs. (\ frac { 1890 }{ 14 })

and cost of 6 m = Rs. (\ frac { 1890times 6 }{ 14 })

= Rs. 135 x 6

= Rs. 810

**Question 2.****Solution:**

Cost of 1 dozen or 12 soaps = Rs. 285.60

Cost of 1 soap = Rs. (\ frac { 285.60 }{ 12 })

Cost of 15 soaps = Rs. (\ frac { 285.60times 15 }{ 12 })

= Rs. 357.00

**Question 3.****Solution:**

Cost of 9 kg of rice = Rs. 327.60

Cost of 1 kg = Rs. (\ frac { 327.60 }{ 9 })

and cost of 50 kg = Rs. (\ frac { 327.60times 50 }{ 9 })

= Rs. 36.40 x 50

= Rs. 1820

**Question 4.****Solution:**

Weight of 22.5 metres of the iron rod: = 85.5 kg

Weight of 1 metre of the iron rod

**Question 5.****Solution:**

Quantity of oil in 15 tins = 234 kg

Quantity of oil in 1 tin = (\ frac { 234 }{ 15 }) kg

Quantity of oil in 10 tins

**Question 6.****Solution:**

Distance covered by the car in 12 litres of diesel = 222 kms

Distance covered by the car in 1 litre of diesel = (\ frac { 222 }{ 12 }) km

**Question 7.****Solution:**

Charges of 25 tonnes of weight = Rs. 540

charges of 1 ton = Rs.(\ frac { 540 }{ 25 })

**Question 8.****Solution:**

Weight of copper in 4.5 g of alloy = 3.5g

Weight of copper in 1 g of alloy

**Question 9.****Solution:**

In Rs. 87.50, the inland letter are purchased = 35

In Re. 1, letters can be purchased

= (\ frac { 35 }{ 87.50 })

and in Rs. 315, letters can be purchased

**Question 10.****Solution:**

4 dozen = 4 x 12 = 48 bananas

In Rs. 104, banana are purchased = 48

**Question 11.****Solution:**

In Rs. 22770, chairs are purchased =18

In Re. 1, chairs will be purchased

= (\ frac { 18 }{ 22770 })

and in Rs. 10120, chairs will be

purchased = (\ frac { 18times 10120 }{ 22770 })

= 8

**Question 12.****Solution:**

(i) A car travels 195 km distance in = 3 hours

It will travel 1 km distance in = (\ frac { 3 }{ 195 }) hr.

and it will travel 520 km distance in

= (\ frac { 3times 520 }{ 195 })

= 8 hr

(ii) A car travels in 3hr = 195 km

**Question 13.****Solution:**

(i) A laborer earn in 12 days = Rs. 1980

He will earn in 1 day = Rs. (\ frac { 1980 }{ 12 })

and he will earn in 7 days

**Question 14.****Solution:**

(i) Weight of 65 books = 13 kg

Then weight of 1 book = (\ frac { 13 }{ 65 }) kg

**Question 15.****Solution:**

Number of boxes needed for 6000 pens = 48

Number of boxes needed for 1 pen 48 = (\ frac { 48 }{ 6000 })

**Question 16.****Solution:**

Clearly, less workers will build the wall in more days.

And, more workers will build the wall in less days.

24 workers can build the wall in 15 days

1 worker can build the wall in (15 x 24) days

(less worker, more days)

9 workers will build the wall in

**Question 17.****Solution:**

Men needed to finish a piece of work in 26 days = 40

Men needed to finish a piece of work in 1 day = 40 x 26 (less days, more men)

**Question 18.****Solution:**

Clearly, less men will take more days to consume the food.

And, more men will take less days to consume the food.

550 men have provisions for 28 days

1 men has provisions for (28 x 550) days [less men, more days]

700 men will have provisions for

**Question 19.****Solution:**

Clearly, less persons will consume the rice in more days.

And more persons will consume the rice in less days.

60 persons consume the bag of rice in 3 days.

1 person will consume the bag of rice in

(3 x 60) days (less persons, more days)

18 persons will consume the bag of rice

Hope given RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10C are helpful to complete your math homework.

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