# RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A - Learn Hool

## RS Aggarwal Class 6 Solutions Chapter 6 Simplification Ex 6A

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 6 Simplification Ex 6A.

Other Exercises

Simplify

Question 1.
Solution:
21 – 12 ÷ 3 x 2
= 21 – 4 x 2
= 21 – 8
= 13. Ans

Question 2.
Solution:
16 + 8 ÷ 4 – 2 x 3
= 16 + 2 – 2 x 3
= 16 + 2 – 6
= 18 – 6
= 12. Ans.

Question 3.
Solution:
13 – (12 – 6 ÷ 3)
= 13 – (12 – 2)
= 13 – (10)
= 13 – 10
= 3 Ans.

Question 4.
Solution:
19 – [4 + {16 – (12 – 2)}]
= 19 – [4 + {16 – 10}]
= 19 – [4 + 6]
= 19 – 10
= 9. Ans

Question 5.
Solution:
36 – [18 – {14 – (15 – 4 ÷ 2 x 2)}]
= 36 – [18 – {14 – (15 – 2 x 2)}]
= 36 – [18 – {14 – (15 – 4)}]
= 36 – [18 – {14 – 11}]
= 36 – [18 – 3]
= 36 – 15
= 21. Ans.

Question 6.
Solution:
(27-[18-{ 16-(5-overline { 4-1 })} ] )
= 27 – [18 – {16 – (5 – 3)}]
= 27 – [18 – {16 – 2}]
= 27 – [18 – 14]
= 27 – 4
= 23. Ans.

Question 7.
Solution:
(4frac { 4 }{ 3 } div frac { 3 }{ 5 } of5+frac { 4 }{ 5 } times frac { 3 }{ 10 } -frac { 1 }{ 5 })

Question 8.
Solution:
(left( frac { 2 }{ 3 } +frac { 4 }{ 9 } right) offrac { 3 }{ 5 } div 1frac { 2 }{ 3 } times 1frac { 1 }{ 4 } -frac { 1 }{ 3 })

Question 9.
Solution:
(7frac { 1 }{ 3 } div frac { 2 }{ 3 } of2frac { 1 }{ 5 } +1frac { 3 }{ 8 } div 2frac { 3 }{ 4 } -1frac { 1 }{ 2 })

Question 10.
Solution:
(5frac { 1 }{ 7 } -left{ 3frac { 3 }{ 10 } div left( 2frac { 4 }{ 5 } -frac { 7 }{ 10 } right) right})

Question 11.
Solution:
(9frac { 3 }{ 4 } div left[ 2frac { 1 }{ 6 } +left{ 4frac { 1 }{ 3 } -left( 1frac { 1 }{ 2 } +1frac { 3 }{ 4 } right) right} right] )

Question 12.
Solution:
(4frac { 1 }{ 10 } -left[ 2frac { 1 }{ 2 } -left{ frac { 5 }{ 6 } -left( frac { 2 }{ 5 } +frac { 3 }{ 10 } -frac { 4 }{ 15 } right) right} right] )

Question 13.
Solution:
(1frac { 5 }{ 6 } +left[ 2frac { 2 }{ 3 } -left{ 3frac { 3 }{ 4 } left( 3frac { 4 }{ 5 } div 9frac { 1 }{ 2 } right) right} right] )

Question 14.
Solution:
(4frac { 4 }{ 5 } div left{ 2frac { 1 }{ 5 } -frac { 1 }{ 2 } left( 1frac { 1 }{ 4 } -overline { frac { 1 }{ 4 } -frac { 1 }{ 5 } } right) right})

Question 15.
Solution:
(7frac { 1 }{ 2 } -left[ 2frac { 1 }{ 4 } div left{ 1frac { 1 }{ 4 } -frac { 1 }{ 2 } left( frac { 3 }{ 2 } -overline { frac { 1 }{ 3 } -frac { 1 }{ 6 } } right) right} right] )

Hope given RS Aggarwal Solutions Class 6 Chapter 6 Simplification Ex 6A are helpful to complete your math homework.

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