Selina Concise Mathematics Class 8 ICSE Solutions Chapter 2 Exponents (Powers)
Selina Publishers Concise Mathematics Class 8 ICSE Solutions Chapter 2 Exponents (Powers)
Exponents Exercise 2A – Selina Concise Mathematics Class 8 ICSE Solutions
Question 1.
Evaluate:
Solution:
Question 2.
If 1125 = 3m x 5n; find m and n.
Solution:
Question 3.
Find x, if 9 × 3x = (27)2x-3
Solution:
Exponents Exercise 2B – Selina Concise Mathematics Class 8 ICSE Solutions
Question 1.
Compute:
Solution:
Question 2.
Simplify:
(i) (8^{frac{4}{3}}+25^{frac{3}{2}}-left\\(\\frac{1}{27}right)^{-frac{2}{3}})
(ii) [(64)-2]-3 ÷ [{(-8)2}3]2
(iii) (2-3 – 2-4) (2-3 + 2-4)
Solution:
Question 3.
Evaluate:
Solution:
Question 4.
Simplify:
Solution:
Question 5.
Simplify:
(xa+b)a-b.(xb+c)b-c.(xc+a)c-a
Solution:
Question 6.
Simplify:
(i) (sqrt[5]{x^{20} y^{-10} z^{5}}+frac{x^{3}}{y^{3}})
(ii) (left\\(\\frac{256 a^{16}}{81 b^{4}}right)^{frac{-3}{4}})
Solution:
Question 7.
(i) (a-2)-2. (ab)-3
(ii) (xny-m)4 × (x3y-2)-n
(iii) (left\\(\\frac{125 a^{-3}}{y^{6}}right)^{frac{-1}{3}})
(iv) (left\\(\\frac{32 x^{-5}}{243 y^{-5}}right)^{frac{-1}{5}})
(v) (a-2b)1/2 × (ab-3)1/3
(vi) (xy)m-n . (yz)n-1 . (zx)1-m
Solution:
Question 8.
Show that:
Solution:
Question 9.
Evaluate:
Solution:
Question 10.
Evaluate:
Solution:
Question 11.
(m + n)-1 (m-1 + n-1) = (mn)-1
Solution:
Question 12.
Prove that:
Solution:
Question 13.
Find the values of n, when:
(i) 12-5 × 122n+1 = 1213 ÷ 127
(ii) \\(\\frac{a^{2 n-3} timesleft(a^{2} cdotright)^{n+1}}{left(a^{4}right)^{-3}}) = (a3)3 ÷ (a6)-3
Solution:
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Question 14.
Simplify:
Solution: